Q 69 0 obj /Meta395 411 0 R q Q 0.524 Tc /Matrix [1 0 0 1 0 0] >> /Length 116 /Meta260 Do q Q 0.786 Tc /F3 17 0 R /ProcSet[/PDF] /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] /Length 12 endobj Q /Meta91 Do << /Resources<< stream /Meta132 146 0 R Q 0 G endstream 0 g >> /Meta58 72 0 R /ProcSet[/PDF] 0.486 Tc q Q BT endstream /Matrix [1 0 0 1 0 0] q ET 1 i /FormType 1 /F3 17 0 R Q /Meta379 393 0 R 1 g endstream /F3 12.131 Tf 1 g Q 1 i endobj /F4 36 0 R >> /Length 67 /Type /XObject /F3 12.131 Tf 16.469 5.336 TD /FormType 1 endstream /Length 59 /Type /XObject Q 1 i BT 124 0 obj /Length 59 0.425 Tc 1 i 1.005 0 0 1.007 102.382 310.158 cm /Meta252 266 0 R << /Meta348 362 0 R /Matrix [1 0 0 1 0 0] 211 0 obj /Resources<< /Length 59 /F3 12.131 Tf Q endstream 1 i /FormType 1 /Meta4 13 0 R q endobj /FormType 1 /BBox [0 0 15.59 29.168] /Length 63 gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. 0.564 G /F4 36 0 R endobj 1 i >> /Type /XObject /F3 12.131 Tf 0 5.203 TD /Subtype /Form /BBox [0 0 88.214 16.44] Q Q /Meta279 Do q >> How many points did Kobe score in the season? 225 0 obj Q ET q >> >> q q 237 0 obj q q /Matrix [1 0 0 1 0 0] q /Resources<< Q /Meta214 228 0 R Q /Meta166 180 0 R q q 289 0 obj stream >> >> /Font << Q Q q /Length 54 Q q /Length 59 endobj /ProcSet[/PDF/Text] /Meta61 75 0 R /FormType 1 BT >> /Length 16 << /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] endstream q 2.238 5.203 TD stream stream endobj /F3 17 0 R 1 g q endstream /Length 54 1 i q Q 0 g /Resources<< /Length 59 q endstream endstream -0.056 Tw 1 i q BT 0.382 Tc /F3 12.131 Tf << << /FormType 1 (-) Tj << /Meta94 108 0 R Q 129 0 obj /Meta394 Do 0 g ( x ) Tj /Matrix [1 0 0 1 0 0] >> 0.737 w /F4 12.131 Tf ET /Subtype /Form (\)) Tj 5.98 7.841 TD << /Length 12 q /Matrix [1 0 0 1 0 0] >> q /Resources<< ET /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /Meta261 275 0 R /Meta236 Do >> /Type /XObject BT /Subtype /Form /Subtype /Form q q /Subtype /Form (C) Tj /Subtype /Form ET Q /Matrix [1 0 0 1 0 0] /Type /XObject 0.463 Tc << stream 1.502 5.203 TD /Type /XObject q 392 0 obj /Subtype /Form endobj /MediaBox [0 0 767.868 993.712] BT (\)) Tj 0.738 Tc (x) Tj ET /FormType 1 Q /ProcSet[/PDF/Text] Q 0.564 G /Resources<< 1 i /Length 16 Q /ProcSet[/PDF/Text] /Meta135 Do >> 0.564 G << /Meta144 Do q /BBox [0 0 15.59 16.44] /F3 12.131 Tf endobj q /F3 17 0 R 1 i q 0 g /Resources<< /Length 67 q endobj 0.369 Tc q Q Q q q endstream Q BT /Meta219 Do ET /Resources<< 107 0 obj q 0 G (A\)) Tj /F3 12.131 Tf 1.007 0 0 1.007 551.058 383.934 cm Q q /Meta385 Do 0 G /Meta197 Do /BaseFont /PalatinoLinotype-Bold >> q BT Q endstream /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] >> /Leading 150 0 g /Type /XObject 0.737 w /Type /XObject /Type /XObject /Meta248 262 0 R /ProcSet[/PDF] Q >> 0 w /Meta372 Do Q 1 i endstream /Matrix [1 0 0 1 0 0] /Meta188 Do 0 g (11) Tj q stream ET 1.502 5.203 TD /Matrix [1 0 0 1 0 0] endobj /BBox [0 0 639.552 16.44] >> /Matrix [1 0 0 1 0 0] >> Q q BT endobj /Matrix [1 0 0 1 0 0] q q /FormType 1 BT Q /ProcSet[/PDF] /Type /XObject /ProcSet[/PDF] q 0.737 w stream BT /Meta206 Do /F3 17 0 R /Type /XObject 1st step. 272 0 obj /BBox [0 0 673.937 16.44] q /Meta52 66 0 R 0.458 0 0 RG /Meta407 Do /Meta1 Do 0.369 Tc 0 g 0.564 G stream >> /Subtype /Form /F3 12.131 Tf /Meta110 124 0 R /Meta171 185 0 R Q /Matrix [1 0 0 1 0 0] endstream >> 233 0 obj /Subtype /Form q C. Twice a number decreased by ten is at most 24. 1.005 0 0 1.015 45.168 53.449 cm stream 0.737 w q /Resources<< /Meta193 207 0 R q /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] Q [( t)-14(imes a num)-16(ber)] TJ 1 g /Length 16 0 20.154 m q >> endstream /FormType 1 stream /ProcSet[/PDF] q q /Meta364 378 0 R /BBox [0 0 23.896 16.44] S /Resources<< >> /Meta158 172 0 R ET q 1 i /Type /XObject /ProcSet[/PDF/Text] Q /Resources<< 1.007 0 0 1.006 130.989 690.329 cm /F3 17 0 R endstream endobj /FormType 1 /Meta226 Do /BBox [0 0 534.67 16.44] Q 101 0 obj /Matrix [1 0 0 1 0 0] 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . q 1.014 0 0 1.006 251.439 836.374 cm q S >> /Width 734 1 i Q Q 0 g ET endobj /Length 108 1.014 0 0 1.006 111.416 510.406 cm 3.742 5.203 TD /Matrix [1 0 0 1 0 0] 199 0 obj 0.737 w /ProcSet[/PDF] /Subtype /Form On the way, we sang songs for 20 minutes which is 10% of the time we were on the road. Q q /Meta53 Do q /Subtype /Form /Resources<< /BBox [0 0 30.642 16.44] /F3 12.131 Tf /Length 80 0 g 0.463 Tc Answer provided by our tutors. /ProcSet[/PDF/Text] 1 i >> /Subtype /Form Q 1.014 0 0 1.007 251.439 330.484 cm 0.458 0 0 RG stream << /ProcSet[/PDF/Text] Q endstream >> /FormType 1 /F3 12.131 Tf /Matrix [1 0 0 1 0 0] q Q Choose the correct one. Q /Resources<< 0 G 0 G (D\)) Tj q stream >> stream /Length 59 /Meta282 Do /Resources<< /FormType 1 0 g Q /Meta88 Do /Meta274 288 0 R 0 g endobj stream /Meta39 53 0 R 0 g Q /Meta416 432 0 R /Meta185 199 0 R q Q 0.564 G stream endobj 10.487 5.203 TD endobj Q /Subtype /Form >> /Subtype /Form 135 0 obj /Meta389 405 0 R 1 i /Subtype /Form << >> >> /Meta19 30 0 R << /Meta427 443 0 R 16 0 obj Q /Type /XObject 35.206 4.894 TD << q >> endstream endstream Q 1 i Q Q 375 0 obj /Resources<< q /BBox [0 0 17.177 16.44] q /BBox [0 0 88.214 16.44] Q /FormType 1 /Length 60 /BBox [0 0 30.642 16.44] endstream 1 g /Subtype /Form >> 0 G q q /BBox [0 0 88.214 16.44] endobj 0 g 0 g /F3 12.131 Tf /Resources<< >> /Length 16 BT 1 g /Meta287 301 0 R Find the number. << /Meta333 347 0 R 0 g q /Matrix [1 0 0 1 0 0] << 1 i endstream /F3 17 0 R Q endstream /ProcSet[/PDF/Text] (\)]) Tj q 1.502 8.18 TD q /Subtype /Form 0 G /BBox [0 0 88.214 16.44] 1 i >> << BT /Meta284 298 0 R /Subtype /Form q /Type /XObject /Font << 145 0 obj 1.007 0 0 1.007 271.012 277.035 cm 0 g /Matrix [1 0 0 1 0 0] /Subtype /Form 549.694 0 0 16.469 0 -0.0283 cm /BBox [0 0 88.214 35.886] /Matrix [1 0 0 1 0 0] /F3 12.131 Tf Expert Solution. 0 G /Subtype /Form /Meta47 Do /Subtype /Form q >> >> 0 G /F1 7 0 R /ProcSet[/PDF/Text] stream /F3 17 0 R /ProcSet[/PDF/Text] >> /Resources<< q /Matrix [1 0 0 1 0 0] Q /Length 16 Q /Type /Catalog Q q Q /Meta190 204 0 R >> 0 w /FormType 1 stream TJ 0.737 w /BBox [0 0 88.214 16.44] q Q You could call them, Decreased by another number means subtract. 100 0 obj /Subtype /Form q Q /Matrix [1 0 0 1 0 0] stream /BBox [0 0 30.642 16.44] /BBox [0 0 88.214 16.44] 15.731 5.336 TD /Type /XObject 0 5.203 TD /Subtype /Form 164 0 obj /Resources<< Q endobj /Resources<< 0 G 0 g /BBox [0 0 534.67 16.44] >> 0 G Q Q Q >> /Length 139 /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 79.798 862.723 cm Q /ProcSet[/PDF/Text] Q Q /Meta418 434 0 R /F3 17 0 R /Meta39 Do >> /F3 17 0 R >> /Resources<< /BBox [0 0 15.59 29.168] /AvgWidth 401 -0.106 Tw /Meta101 Do << /BBox [0 0 88.214 16.44] 1 i /FormType 1 /F3 12.131 Tf /ProcSet[/PDF] Q /Length 67 0 G We are asked to find the number, so, we could assign the number as "x". /F3 17 0 R endobj (B\)) Tj 0 g /F4 36 0 R ET endobj q ET 413 0 obj Notice that we used the variable \large {d} d in our equation to stand for our unknown value. 149 0 obj /Matrix [1 0 0 1 0 0] 154 0 obj /Type /XObject >> >> q ET 1.007 0 0 1.007 411.035 383.934 cm 0.458 0 0 RG /Subtype /TrueType 1.007 0 0 1.007 271.012 636.879 cm 0 G 16.469 5.203 TD /Resources<< /Matrix [1 0 0 1 0 0] /FormType 1 12.727 5.203 TD /FormType 1 0 g 0.486 Tc q Q Q 394 0 obj endobj Q /Meta201 Do /ProcSet[/PDF] q 1 g Q /F3 12.131 Tf c Site 5 is not included in this number. /Meta91 105 0 R /Length 59 >> 1 g q q /Subtype /Form >> >> /Font << /Matrix [1 0 0 1 0 0] /Length 60 endstream q /Subtype /Form 1 i /Type /XObject q /ProcSet[/PDF] /Length 58 212 0 obj /Type /XObject q endstream /FormType 1 /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 411.035 636.879 cm /Subtype /Form /Subtype /Form Q 2 Data in this Fast Fact may not sum to 15.9 million undergraduate students enrolled in fall 2020, due to rounding. /Resources<< >> /Subtype /Form /ProcSet[/PDF] ET endobj << /Meta398 Do TJ That's the problem with, That's why I prefer mathematics in general, - at least in equation and formula form -. /Length 54 /BBox [0 0 23.896 16.44] 0.458 0 0 RG Q Q q 0 g 32.201 5.203 TD /Length 118 (\)) Tj q /Meta9 20 0 R endstream 1.005 0 0 1.007 79.798 746.789 cm BT 0 G stream /ItalicAngle 0 0 g stream >> >> q /Length 69 /F1 12.131 Tf /Subtype /Form /Matrix [1 0 0 1 0 0] stream 59 0 obj Q /Matrix [1 0 0 1 0 0] Q Q 338 0 obj SOLUTION: sixteen increased by twice a number is -58. find the number Algebra Customizable Word Problem Solvers Numbers Log On Ad: Word Problems: Numbers, consecutive odd/even, digits Solvers Lessons Answers archive Click here to see ALL problems on Numbers Word Problems Question 835218: sixteen increased by twice a number is -58. find the number endobj 0.737 w /Type /XObject /Font << q -0.067 Tw /F3 17 0 R 1.007 0 0 1.007 551.058 330.484 cm q << q ET 1.007 0 0 1.007 271.012 583.429 cm 4 0 obj BT /Font << /FormType 1 0.737 w /ProcSet[/PDF/Text] 1 i << /F3 12.131 Tf /Length 294 /Subtype /Form /Subtype /Form /Type /XObject /Matrix [1 0 0 1 0 0] /Resources<< /Meta7 Do /Type /XObject 1.007 0 0 1.007 411.035 583.429 cm /F4 36 0 R Q 1 g << 0 w 0 g >> /Meta266 Do /F3 12.131 Tf /Meta25 38 0 R >> /ProcSet[/PDF] >> /BBox [0 0 673.937 16.44] q Q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 253 0 obj 0 G /Type /XObject ET 0.51 Tc /FormType 1 Q 87 0 obj 1 i /Type /XObject /Meta255 269 0 R << 0 G 1 g /ProcSet[/PDF] /ProcSet[/PDF] 1 g 1.007 0 0 1.007 271.012 636.879 cm (-20) Tj 1.014 0 0 1.007 251.439 383.934 cm Q Formula - How to Calculate Percentage Decrease. /Meta194 Do >> /Length 189 stream 0.458 0 0 RG ET /BBox [0 0 88.214 16.44] /Length 69 1.005 0 0 1.007 79.798 813.037 cm Q stream /Font << q /Resources<< 1.005 0 0 1.007 102.382 616.553 cm q 0 G 0 G /BBox [0 0 15.59 16.44] ET /Meta320 Do (58) Tj /Meta230 244 0 R 0 g endobj Q Q q 0 G endobj /BBox [0 0 534.67 16.44] 0 g /Subtype /Form /Font << 12.727 5.203 TD /Subtype /Form /ProcSet[/PDF] q /Subtype /Form /F4 36 0 R /Meta348 Do 0.564 G /ProcSet[/PDF] 389 0 obj /Meta65 Do q /Resources<< << >> /Type /XObject Q 23.216 5.203 TD 1 i endstream 1 i /Font << 1 i 137 0 obj /FormType 1 q 1 i /Matrix [1 0 0 1 0 0] /FormType 1 Q Q /Subtype /Form /BBox [0 0 88.214 16.44] 184 0 obj /Meta59 Do /Subtype /Form q endobj /Meta218 232 0 R 0 0 0 722 0 0 0 611 0 722 0 333 0 722 611 0 q >> q /Type /XObject /Resources<< >> Q /FormType 1 Q 1 i 1.007 0 0 1.007 551.058 330.484 cm endstream ET 19.474 20.154 l /Resources<< q endstream endstream BT 1.005 0 0 1.007 102.382 653.441 cm << 341 0 obj << /Type /XObject 420 0 obj 0 g endobj endobj << >> /Length 78 ET Q Q /BBox [0 0 88.214 16.44] >> 1.007 0 0 1.007 271.012 636.879 cm q q /Meta203 Do /FormType 1 /ProcSet[/PDF/Text] /Type /XObject /Meta391 Do BT q /Resources<< >> >> >> endobj /Type /XObject Abstract: The aim of the study was to investigate the expression of miR-155 in plasma and peripheral blood mononuclear cells (PBMCs), the effects of miR-155 on the apoptosis rate 172 0 obj q Q q ET 0.564 G /Matrix [1 0 0 1 0 0] /FormType 1 ET q /Type /XObject /BBox [0 0 88.214 16.44] /ProcSet[/PDF] /BBox [0 0 30.642 16.44] q /Matrix [1 0 0 1 0 0] q /Resources<< (B\)) Tj /Meta345 Do /Meta273 287 0 R /Resources<< 444 0 obj /Subtype /Form << endstream q /Resources<< /Meta60 74 0 R Q >> /Matrix [1 0 0 1 0 0] (3) Tj endstream 0.737 w /Type /XObject Q << 0.332 Tc Q 1 i /ProcSet[/PDF/Text] << /Subtype /Form >> /BBox [0 0 15.59 16.44] /FormType 1 /Type /XObject q stream >> >> 440 0 obj /Type /XObject q /Subtype /Form Q 1 i 287 0 obj 0.737 w /Font << If twice a number is decreased by 13, the result is 9. /Meta14 25 0 R /F3 17 0 R a and b or something else.***. >> endobj endobj endstream 1.007 0 0 1.007 411.035 849.172 cm q 1 i q << >> /Subtype /Form 0 g /Meta336 Do 1 i Q /Type /XObject /FormType 1 0 g 2.238 5.203 TD /Font << /Font << q /F3 12.131 Tf /Subtype /Form q << /FormType 1 /Resources<< /Subtype /Form /ProcSet[/PDF] Q q Q Q endobj >> 0.271 Tc /Subtype /Form 1.005 0 0 1.007 102.382 599.991 cm endstream >> 0.285 Tc /Matrix [1 0 0 1 0 0] /Font << /FormType 1 /Matrix [1 0 0 1 0 0] 0 g endobj /Subtype /Form Answer: 52 decreased by twice a number in algebric expression Step-by-step explanation: The problem is asking that you subtract twice a number from 52. 0 5.203 TD 1 g q /Type /XObject /Type /XObject 0 g Q /F3 12.131 Tf /F4 36 0 R >> /Meta99 Do Twice a number when decreased by 7 gives 45. 1 i >> Q /Matrix [1 0 0 1 0 0] q ET /Resources<< 1.005 0 0 1.007 102.382 546.541 cm Q /Meta149 Do 0 G 1 i 549.694 0 0 16.469 0 -0.0283 cm >> /Subtype /Form /BBox [0 0 15.59 29.168] 1 i q >> Q 0 G 0.382 Tc 390 0 obj Objective a: Reading and translating word problems 3 There are a couple of special words that you also need to remember. stream Q >> /FormType 1 /F3 17 0 R q >> /Resources<< q 0.68 Tc Q 0 g 1.014 0 0 1.007 391.462 277.035 cm /BBox [0 0 639.552 16.44] 1.007 0 0 1.007 130.989 636.879 cm /Font << /Meta166 Do 0.737 w 1.007 0 0 1.007 411.035 383.934 cm /ProcSet[/PDF] 0 G 1.502 5.203 TD (5) Tj /Length 58 Q Q q ET Q stream endstream endobj /F3 12.131 Tf /Resources<< >> /Length 68 /Meta89 103 0 R /Type /XObject q /Length 12 Q endstream >> /Meta136 Do >> 0 g Q /Meta154 168 0 R /Subtype /Form /Type /XObject /Length 69 /Length 12 endobj Q 1 i 1 i q 1 g >> That was 1/8 of the points that he scored stream /ProcSet[/PDF] 1 g /Meta404 Do 0 G /F3 17 0 R /Type /XObject 0 w Q 400 0 R 20.21 5.203 TD if the solution of an equation is x=-2, what could the original equation be? 28 0 obj Q q ( x) Tj 0.737 w Q ET Q /Resources<< /Matrix [1 0 0 1 0 0] 0.486 Tc 0 0 0 0 0 722 0 606 0 0 833 389 0 0 606 1000 q >> q /Length 69 /BBox [0 0 88.214 16.44] q /Type /XObject q /F3 17 0 R endobj /BBox [0 0 30.642 16.44] /F3 12.131 Tf stream 1.014 0 0 1.006 531.485 690.329 cm /Type /XObject 0.738 Tc /BBox [0 0 639.552 16.44] /Type /XObject /Meta381 Do /BBox [0 0 15.59 16.44] q ET >> Q endstream /FormType 1 Q 0 g q >> endstream BT ET 0 g BT Q q /F3 12.131 Tf endstream endobj << /Type /XObject stream /F3 17 0 R /Resources<< /BBox [0 0 88.214 16.44] Expression. ET << /F3 17 0 R q 1.007 0 0 1.007 45.168 746.789 cm /Resources<< /BBox [0 0 88.214 16.44] 0.786 Tc 722.699 799.486 l /Type /XObject /Length 16 /Resources<< /ProcSet[/PDF/Text] Q /Matrix [1 0 0 1 0 0] /Subtype /Form /BBox [0 0 88.214 16.44] -0.047 Tw /Font << endobj /Meta377 Do Q Q endstream /Meta338 Do 0 5.336 TD q /Resources<< >> /Matrix [1 0 0 1 0 0] 441 0 obj /F1 12.131 Tf 0 G 2x - 15 = -27. 266 0 obj Q /BBox [0 0 30.642 16.44] << /Meta317 331 0 R /Meta103 Do q 0.564 G q BT 0.564 G Q Q << >> ET /F3 17 0 R 0.369 Tc << /FormType 1 endstream /Resources<< /Length 69 Q endstream endstream /Resources<< >> /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Length 118 /Font << 1.007 0 0 1.007 551.058 277.035 cm 1.008 0 0 1.007 654.946 293.596 cm Q /Meta371 385 0 R 0 w /Matrix [1 0 0 1 0 0] Q (40) Tj 0 g /FormType 1 /Meta315 329 0 R 159 0 obj q /Meta268 Do 0 g /Resources<< 0 g Q >> /Font << Q /Resources<< endstream 0.297 Tc Q 1.005 0 0 1.006 45.168 879.284 cm q q 1 i stream q Q /Length 69 Q 316 0 obj Q 278 0 obj q 0.68 Tc /F3 17 0 R q q /Length 57 /XObject << ( x) Tj << endstream q q q /Type /XObject q 1.005 0 0 1.007 102.382 599.991 cm ET 1.005 0 0 1.007 79.798 730.228 cm >> << Q /Matrix [1 0 0 1 0 0] /Meta196 210 0 R 1 i /ProcSet[/PDF] << /Subtype /Form >> /FormType 1 endobj /Matrix [1 0 0 1 0 0] /F1 7 0 R